21laila21
21laila21 21laila21
  • 19-07-2020
  • Mathematics
contestada

Evaluate
[tex]lim \: \frac{1 - cosx }{ {x}^{2} \sin(x) } \: as \: x \: approches \: {0}^{ + } [/tex]
​

Respuesta :

r3t40
r3t40 r3t40
  • 19-07-2020

[tex]

\lim_{x\to0^+}\frac{1-\cos(x)}{x^2\sin(x)}=\frac{1-\cos(0^+)}{0^+^2\sin(0^+)\frac{0^+}{+\infty}=\boxed{0^+}

[/tex]

Hope this helps.

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