Respuesta :

CSMedrano

Answer:

y=(x+1)^2

Step-by-step explanation:

we have the following

[tex]x=1;y=4\\\\x=2;y=9\\\\x=3;y=16\\\\x=4;y=25[/tex]

the values of y are squares so we can write

[tex]x=1;y=2^{2} \\\\x=2;y=3^2\\\\x=3;y=4^2\\\\x=4;y=5^2[/tex]

so as you can see when

[tex]x=n;y=(n+1)^2[/tex]

so our relation is

[tex]y=(x+1)^2[/tex]

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