Respuesta :

CSMedrano

Answer:

h=2x

p=(VL/2)-k

Step-by-step explanation:

solving for h

[tex]2h=4x\\\\\frac{1}{2}*2h= \frac{1}{2} *4x\\\\h=2x[/tex]

solving for p

[tex]VL=2p+2k\\\\VL-2k=2p+2k-2k\\\\VL-2k=2p\\\\\frac{1}{2}*2 p=\frac{VL-2k}{2} \\\\p=\frac{VL}{2} -k[/tex]

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