Answer:
E. 120
Step-by-step explanation:
A. 40
B. 72
C. 80
D. 100
E. 120
Let
x = the intended distance
y = length of the pool
She covers one fifth of her intended distance
Distance covered = 1/5 of x
= x/5
After swimming six more lengths of the pool she had covered one quarter of her intended distance
x/5 + 6y = 1/4 of x
x/5 + 6y = x/4
Collect like terms
6y = x/4 - x/5
6y = 5x - 4x/20
6y = x/20
x = 20 * 6y
= 120y
x = 120y
The intended distance Rebecca wants to cover = 120
