esteban79
contestada

PLEASE HELP
At a circus, a human cannonball is shot from a cannon at 15m/s at an angle of 40° above horizontal. She
leaves the cannon 2m off the ground and lands in a net 1m off the ground. What height does she reach?
How much ground distance does she cover?

Respuesta :

Answer:

Explanation:

[tex]a_{x}=0[/tex] [tex]v_{xo}= v_{o}cos(delta)t[/tex] [tex]a_{y}=-g[/tex] [tex]v_{yo}=sin[/tex]θ

X-direction                                     | Y-direction

[tex]x=x_o+v_{xo}t[/tex] ⇒ [tex]x=v_{xo}cos(delta)t[/tex] |

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