mwickerh mwickerh

19-11-2014
Mathematics

contestada

[tex]5= x^{2} +2x[/tex]

solve the equation using any method you prefer. Give imaginary roots.

Respuesta :

konrad509 konrad509

19-11-2014

[tex]5=x^2+2x\\ x^2+2x-5=0\\ x^2+2x+1-6=0\\ (x+1)^2=6\\ x+1=\sqrt6 \vee x+1=-\sqrt6\\ x=-1+\sqrt6 \vee x=-1-\sqrt6[/tex]

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