Answer:
1.47 x 10⁻¹⁹J
Explanation:
Given parameters;
Frequency of wave = 2.22 x 10¹⁴/s
Unknown:
Energy of the photon = ?
Solution:
The energy of a photon can be mathematically derived using the expression below;
E = hf
E is the energy
h is the Planck's constant = 6.63 x 10⁻³⁴m²kg/s
f is the frequency
Insert the parameters and solve;
E = 6.63 x 10⁻³⁴m²kg/s x 2.22 x 10¹⁴/s
E = 14.7 x 10⁻²⁰J or 1.47 x 10⁻¹⁹J
