Nemisisxd Nemisisxd
  • 18-11-2020
  • Mathematics
contestada

If HF=4x+9, EF = 5x+3 , and EF is perpendicular to HF, solve for x.

If HF4x9 EF 5x3 and EF is perpendicular to HF solve for x class=

Respuesta :

akposevictor
akposevictor akposevictor
  • 25-11-2020

Answer:

x = 6

Step-by-step explanation:

HF = 4x + 9

EF = 5x + 3

Since FG is perpendicular to EH, ∆EFG and ∆HFG are congruent to each other.

Thus:

HF = EF

4x + 9 = 5x + 3 (substitution)

Collect like terms

4x - 5x = -9 + 3

-x = -6

Divide both sides by -1

x = 6

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