Answer:
64 byte of memory
Explanation:
The computer has 8 bytes addressability and the memory only requires 3 bits to access its entire memory size. Remember that a computer is an electronic device and it stores data and receives instructions in binary of 1 and 0. So for an eight-byte addressable computer,
total memory size = 2^(3 bits) x 8 (computer's addressability)
= 8 x 8
= 64 bytes of memory.
