Samithginaksash Samithginaksash
  • 20-10-2016
  • Chemistry
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How can I draw the Lewis structure for ClO2-?

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Loliypop3
Loliypop3 Loliypop3
  • 20-10-2016
The valence electrons you have available are: 1 Cl + 2 O + 1 e=1×7+2×6+1=20 . Hence, the trial structurehas the correct number of electrons. We can reduce the number of formal charges by moving a lone pair of electrons from O to form a Cl=O. double bond.
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