Answer:
0.55m
Explanation:
Given parameters:
Spring constant = 1800N/m
Elastic potential energy = 270J
Unknown:
extension = ?
Solution:
To solve this problem, we use the formula of the elastic potential energy;
E. P = [tex]\frac{1}{2}[/tex] k e²
E.P is the elastic potential energy
k is the spring constant
e is the extension
270 = [tex]\frac{1}{2}[/tex] x 1800 x e²
e = 0.55m
