Answer:
d = 61.75 m
Explanation:
Given that,
A ball droped from a building.
We need to find how fast is it traveling after falling 3.55 s.
As it is dropped, its initial velocity is equal to 0.
Let d is the distance it covers after falling 3.55 s.
We can use second equation of motion to find d.
[tex]d=ut+\dfrac{1}{2}at^2[/tex]
Here, u = 0 and a =g
[tex]d=\dfrac{1}{2}gt^2\\\\d=\dfrac{1}{2}\times 9.8\times (3.55)^2\\\\d=61.75\ m[/tex]
So, it will cover 61.75 m after falling 3.55 seconds.
