Answer:
E =250 J
Explanation:
Given that,
The spring constant of the spring, k = 500 N/
It is stretched to a distance of 1 m
We need to find how much elastic potential energy does the spring have stored in it.
The energy stored in the spring is called elastic potential energy. It is given by the formula as follows :
[tex]E=\dfrac{1}{2}kx^2\\\\E=\dfrac{1}{2}\times 500\times 1^2\\\\E=250\ J[/tex]
So, 250 J of energy is stored in the spring.
