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In a right ABC with B and C complementary, sin B = p and cos B = q. What is sin C – cos C?

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Answer:

  q - p

Step-by-step explanation:

For complementary angles B and C, ...

  cos(C) = sin(B) = p

  sin(C) = cos(B) = q

Then the difference is ...

  sin(C) -cos(C) = q - p