elcuhhhh1323 elcuhhhh1323
  • 18-02-2021
  • Mathematics
contestada

Find the value of c so that (x+3) is a factor of the polynomial p(x). p(x)=x^3-4x^2+cx+33

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joaobezerra joaobezerra
  • 23-02-2021

Answer:

The value of c is -10.

Step-by-step explanation:

Since (x+3) is a factor of the polynomial p(x).

We have that:

x + 3 = 0 -> x = -3

So p(-3) = 0

Then

[tex]p(x) = x^3 - 4x^2 + cx + 33[/tex]

[tex](-3)^3 - 4(-3)^2 - 3c + 33 = 0[/tex]

[tex]-27 - 36 - 3c + 33 = 0[/tex]

[tex]3c = -30[/tex]

[tex]c = -\frac{30}{3}[/tex]

[tex]c = -10[/tex]

The value of c is -10.

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