Answer:
0 real roots
Step-by-step explanation:
Given a quadratic equation in standard form
ax² + bx + c = 0 ( a ≠ 0 )
Then the discriminant is
Δ = b² - 4ac
• If b² - 4ac > 0 then 2 real and distinct roots
• If b² - 4ac = 0 then 2 real and equal roots
• If b² - 4ac < 0 then the roots are not real
- 9x² + x - 7 = 0 ← is in standard form
with a = - 9, b = 1, c = - 7 , then
b² - 4ac = 1² - (4 × - 9 × - 7) = 1 - 252 = - 251
Since b² - 4ac < 0 then the equation has no real roots
