Answer:
[tex] m\angle BFG =\frac{ (m\widehat {GB} + m\widehat {CD})}{2} [/tex]
Step-by-step explanation:
By the property of intersecting chords, we have:
[tex] m\angle BFG =\frac{1}{2} (m\widehat {GB} + m\widehat {CD} ) [/tex]
[tex] m\angle BFG =\frac{ m\widehat {GB} + m\widehat {CD}}{2} [/tex]
