Answer:
129.3 in²
Step-by-step explanation:
The shaded segment is calculated as
area of sector ABC - area of triangle ABC
area of sector = area of circle × fraction of circle
A = πr² × [tex]\frac{60}{360}[/tex]
= π × 18² × [tex]\frac{1}{6}[/tex]
= 324π × [tex]\frac{1}{6}[/tex] = 54π in²
area of Δ ABC = [tex]\frac{1}{2}[/tex] × 18 × 18 × sin60° ≈ 40.30 in²
Then
shaded area = 54π - 40.30 ≈ 129.3 in² ( to the nearest tenth )
