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  • 16-04-2021
  • Mathematics
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Find the 16th term of the geometric sequence 4, -16, 64, ...

Respuesta :

unicorn3125
unicorn3125 unicorn3125
  • 17-04-2021

Answer:

         [tex]\bold{a_{16} =-4^{16}=-2^{32}=-4\,294\,967\,296}[/tex]

Step-by-step explanation:

[tex]a_1=4\\a_2=-16\\a_3=64\\\\\dfrac{a_2}{a_1}=\dfrac{-16}{4}=-4\\\\ \dfrac{a_3}{a_2}=\dfrac{64}{-16}=-4\\\\\\\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}=-4=r[/tex]

The formula:

                     [tex]a_n=a_1\cdot q^{n-1}[/tex]

Therefore:

                 [tex]a_{16} =4\cdot(-4)^{16-1}=4\cdot(-4)^{15}=-4^{16}=-2^{32}=-4\,294\,967\,296[/tex]

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