Step-by-step explanation:
The given vector is :
r = (-4,6)
We can write in the form of vector as follows :
r = -4i+6j
The magnitude of vector r is :
[tex]|r|=\sqrt{-4^2+6^2} \\\\=\sqrt{16+36} \\\\=7.21[/tex]
For direction,
[tex]\tan\theta=\dfrac{y}{x}\\\\\theta=\tan^{-1}(\dfrac{y}{x})\\\\=\tan^{-1}(\dfrac{6}{-4})\\\\=-56.3^{\circ}[/tex]
So, the magnitude is 7.21 and the direction is [tex]-56.3^{\circ}[/tex]
Answer:
A. |r|=2√13, 56.3° N of W
Step-by-step explanation:
got it on edge :)
