The length of a rectangle is 11 units more than its width. The perimeter of the rectangle is 182 units. Solve for the dimensions of the rectangle. What is the area of the rectangle?

rlly need hlp

We are given the perimeter of 182 units and that the lengths are 11 more units than the width. So the length is W+11, eleven more than the width. There is also 2 width sides so the sum of the lengths are 2W+22. There is also 2 width sides so if you add that to the equation the perimeter equals 4W+22.

4W+22=182

4W=160

W=40

So the width is 40 units, and the length is 11 more so the length is 54 units. Multiply these two numbers to get the area. 44*54=2160 square units.

The length of a rectangle is 11 units more than its width. The perimeter of the rectangle is 182 units. Solve for the dimensions of the rectangle. What is the area of the rectangle? rlly need hlp

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The length of a rectangle is 11 units more than its width. The perimeter of the rectangle is 182 units. Solve for the dimensions of the rectangle. What is the area of the rectangle?

rlly need hlp