Answer:
0.24 M
Explanation:
Step 1: Write the balanced neutralization reaction
NaOH + HCl ⇒ NaCl + H₂O
Step 2: Calculate the reacting moles of NaOH
17.89 mL (0.01789 L) of 1 M NaOH react.
0.01789 L × 1 mol/L = 0.01789 mol
Step 3: Calculate the moles of HCl that reacted with 0.01789 moles of NaOH
The molar ratio of NaOH to HCl is 1:1. The moles of HCl that reacted are 1/1 × 0.01789 mol = 0.01789 mol.
Step 4: Calculate the molar concentration of HCl
0.01789 moles are in 75 mL (0.075 L) of HCl,
[HCl] = 0.01789 mol/0.075 L = 0.24 M
