rahimx
rahimx rahimx
  • 17-05-2021
  • Mathematics
contestada

find the values of a and b such that x^2+3x+4=(x+a)^2+b​

Respuesta :

doomdabomb
doomdabomb doomdabomb
  • 17-05-2021

Answer:

a = [tex]\sqrt{x^2+3x+4-b} -x[/tex], [tex]-\sqrt{x^2+3x+4-b}-x[/tex]

b = [tex]x^{2} +3x+4-(x+a)^2[/tex]

Step-by-step explanation:

Answer Link
nightfurythanh12
nightfurythanh12 nightfurythanh12
  • 17-05-2021

Answer:

a= 1.5 ; b = 7/4

Step-by-step explanation:

Magic...

in fact, the key here is

(x+a)^2 = x^2 + 2×x×a +a^2

I believe you can take it from here?

also my calculation can be wrong I did in my head cuz I dont have a proper calculator

Answer Link

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