keeganmyatt keeganmyatt
  • 19-05-2021
  • Chemistry
contestada

How much concentrated 15.54 M sulfuric acid is need to prepare 6.1 mL of a 2.28 M solution?

Respuesta :

samueladesida43
samueladesida43 samueladesida43
  • 24-05-2021

Answer:

0.895 mL

Explanation:

Using the formula;

C1V1 = C2V2

Where;

C1 = initial concentration (M)

C2 = final concentration (M)

V1 = initial volume (mL)

V2 = final volume (mL)

According to the information provided in this question;

C1 = 15.54M

V1 = ?

C2 = 2.28M

V2 = 6.1 mL

Using C1V1 = C2V2

V1 = C2V2 ÷ C1

V1 = (2.28 × 6.1) ÷ 15.54

V1 = 13.908 ÷ 15.54

V1 = 0.895 mL

Answer Link

Otras preguntas

5x² - 20x + k = 0 has exactly one real solution, show that k=20​
codehs how to do 4.1.5 line of increasing blocks
Heres some fr ee points ppl
Answer please answer
Which is the the best way to complete the text? PLEASE HELP
choose the correct aternative: 1)Where did you______yesterday? 2)Did paola_____Ceviche? 3)What___he_____last night? 4)when did your sister_______English? 5)I___
1) Target offers their employees group health insurance and covers 70% of the cost. If the annual premium for the insurance is $12,450.00 how much is deducted f
Can anyone help me solve this?
You start at (6,4) and move 4 units left and 2 units down what point will you end up on?
1.1.4 Which of the following reagents is used to test for glucose? A. Fehling's solution B. Ethanol C. Benedict's solution D. lodine ​