Answer:
[tex]P(Z<-2.5) =0.0062097[/tex]
Step-by-step explanation:
From the question we are told that:
Test statistic t =-2.5
Generally the equation for Test for statistics is mathematically given by
[tex]t=\frac{\=x-\mu}{\frac{s}{\sqrt{n} } }[/tex]
[tex]t=-2.5[/tex]
Therefore
P-value from Z table is
For left tailed test
[tex]P(Z<-2.5) =0.0062097[/tex]
therefore the P-value for the test is
[tex]P(Z<-2.5) =0.0062097[/tex]
