Answer:
The zeros are 1 and 2
Step-by-step explanation:
Given
[tex]y =x^2 - 3x + 2[/tex]
Required
The zeros
[tex]y =x^2 - 3x + 2[/tex]
Expand
[tex]y =x^2 - 2x-x + 2[/tex]
Factorize
[tex]y =x(x - 2)-1(x - 2)[/tex]
Factor out x - 2
[tex]y =(x - 1)(x - 2)[/tex]
Set to 0
[tex](x - 1)(x - 2)=0[/tex]
Solve for x
[tex]x - 1 = 0 \to x =1[/tex]
[tex]x - 2 = 0 \to x =2[/tex]
Hence, the zeros are 1 and 2
