fatmommymilkers
fatmommymilkers fatmommymilkers
  • 18-07-2021
  • Mathematics
contestada

Find the equation of the line that is perpendicular to y=1/6x+3
and contains the point (-3,23).
y = [?]x + [?]

Find the equation of the line that is perpendicular to y16x3 and contains the point 323 y x class=

Respuesta :

Adetunmbiadekunle Adetunmbiadekunle
  • 23-07-2021

Answer:

y = -6x + 6

Step-by-step explanation:

The general equation of a line is

y = mx + b

where m is the slope and b is the y-intercept

The slope in the first equation is 1/6

Mathematically, when two lines are perpendicular, the product of their slopes is -1

1/6 * m2 = -1

m2 = -6

So we have the equation as;

y-y1 = m(x-x1)

y-23 = -6(x + 3)

y = -6x -18 +23

y = -6x + 6

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