crayonconsumer420 crayonconsumer420
  • 21-08-2021
  • Mathematics
contestada

Determine the type and number of solutions of 4x - 4x + 1 = 0.

two real solutions
one real solution
two imaginary solutions​

Respuesta :

Аноним Аноним
  • 21-08-2021

Answer:

1 real solution

Step-by-step explanation:

Use discramint formula.

[tex]b {}^{2} - 4ac[/tex]

If the discramint >0, the equation is going to have 2 real solutions

If the discramint =0, we going to have one real solution.

If the discramint<0, we going to have two imaginary solution

B is -4, A is 4 and C is 1 so

[tex] { - 4}^{2} - 4( 4)(1) = 0[/tex]

So the equation had one real solution.

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