bethanyannprice bethanyannprice
  • 17-09-2021
  • Mathematics
contestada

In the expansion of (ax+1)^7
the fifth term is 945x^3
Find the value of a.

Respuesta :

Izzy274
Izzy274 Izzy274
  • 17-09-2021

Answer:

a = 3

Step-by-step explanation:

First start writing out the binomial expansion of [tex](ax + 1)^7[/tex]

[tex][1^7] + [7C1 * 1^6 *(ax)] + [7C2*1^5*(ax)^2]+[7C3*1^4*(ax)^3][/tex]

as you can see from this, the last bracket will produce our [tex]x^3[/tex] term

[tex]7C3*1^4*a^3x^3 \\35a^3x^3\\35a^3 = 945\\a^3 = 27\\a = 3[/tex]

Hope this helps, let me know if you have any questions :)

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