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Calculate the velocity of a bowling ball thar moves 30.4m along the floor of an alley in 5.4s at a constant rate.

Respuesta :

  • Displacement=30.4m
  • Time=5.4s

[tex]\\ \rm\longmapsto Velocity=\dfrac{Displacement}{Time}[/tex]

[tex]\\ \rm\longmapsto Velocity=\dfrac{30.4}{5.4}[/tex]

[tex]\\ \rm\longmapsto Velocity=5.62m/s[/tex]

Answer:

• from second newtons equation of motion:

[tex]{ \tt{s = ut + \frac{1}{2} {at}^{2} }} \\ [/tex]

• s → 30.4 m

• t → 5.4 s

• a → 0 [ constant velocity ]

[tex]{ \tt{30.4 = (u \times 5.4) + 0}} \\ \\ { \tt{5.4u = 30.4}} \\ \\ { \boxed{ \tt{velocity = 5.63 \: m {s}^{ - 1} }}}[/tex]

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