nastyapetras12 nastyapetras12
  • 19-10-2021
  • Mathematics
contestada

how do you solve this (first equation) x=2y-1 (second equation) x+y=40

Respuesta :

rlesandisusanya
rlesandisusanya rlesandisusanya
  • 19-10-2021

Answer:

[tex]x = 26 \frac{1}{3} \\ [/tex]

[tex]y = 13 \frac{2}{3} \\ [/tex]

Step-by-step explanation:

x = 2y - 1

x - 2y = -1 ________(1)

x + y = 40________(2)

(2) - (1)

[tex]x + y - (x - 2y) = 40 - ( - 1) \\ x + y - x + 2y = 40 + 1 \\ 3y = 41 \\ y = \frac{41}{3} \\ y = 13 \frac{2}{3} \\ [/tex]

y = 13 2/3

[tex]x + y = 40 \\ x + 13 \frac{2}{3} = 40 \\ x = 40 - 13 \frac{2}{3} \\ x = 40 - \frac{41}{3} \\ x = \frac{3(40) - 41}{3} \\ x = \frac{120 - 41}{3} \\ x = \frac{79}{3} \\ x = 26 \frac{1}{3} \\ [/tex]

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