Answer:
y=-4/3x-1
Step-by-step explanation:
[tex] \frac{ {y}^{2} - {y}^{1} }{ {x}^{2 -{x}^{1} } } [/tex]
[tex] \frac{ - 13 - 3}{9 - - 3} = \frac{ - 16}{12\ }[/tex]
y=mx+b like this:
y=-4/3x+b
To find b:
y=-4/3x+b.
You can use either (x,y) point you want..the answer will be the same
(-3,3). y=mx+b or 3=-4/3 × -3+b, or solving for b: b=3-(-4/3)(-3). b=-1.
(9,-13). y=mx+b or -13=-4/3 × 9+b, or solving for b: b=-13-(-4/3)(9). b=-1.
