DavidHarris DavidHarris
  • 17-01-2017
  • Mathematics
contestada

what is the improper fraction of 136/20

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Аноним Аноним
  • 17-01-2017
136 / 20 = (2 3 * 17) / (2 2 * 5) = ((2 3 * 17) : 2 2 ) / ((2 2 * 5) : 2 2 ) = (136 : 4) / (20 : 4) ... 34 > 5 =>improper fraction Rewrite: 34 : 5 = 6 and remainder = 4 => 34 / 5 ...
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Аноним Аноним
  • 17-01-2017
The improper fraction of 136/20 would be 34/5
136 / 20 =
(2^3 * 17) / (2^2 * 5) =
((2^3 * 17) : 2^2) / ((2^2 * 5) : 2^2) =
(136 : 4) / (20 : 4) = 34/5
Hope this helps you!!
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