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  • 21-03-2022
  • Mathematics
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To solve the equation 3 sin(2x) = 5cosx, you should rewrite it as
O A. cosx(3sinx - 5) = 0
0 B. cosx(6sinx - 5) = 0
O C. 3sinx + 5cosx = 0


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To solve the equation 3 sin2x 5cosx you should rewrite it as O A cosx3sinx 5 0 0 B cosx6sinx 5 0 O C 3sinx 5cosx 0 Help me out class=

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subtomex0
subtomex0 subtomex0
  • 21-03-2022

Answer:

OPTION B

Step-by-step explanation:

3sin(2x)=5cos(x)

3×(2sinxcosx)=5cos(x)

6sin(x)cos(x)=5cos(x)

6sin(x)cos(x)-5cos(x)=0 Factor out a cos(x)

cosx(6sinx-5)=0

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