wendle1122
wendle1122 wendle1122
  • 16-08-2022
  • Mathematics
contestada

pythagorean theorem

thanks

pythagorean theorem thanks class=

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Medunno13
Medunno13 Medunno13
  • 16-08-2022

[tex]3^2 + b^2 = 11^2 \\ \\ 9+b^2 = 121 \\ \\ b=\boxed{\sqrt{112}}[/tex]

Answer Link
ashish4112119
ashish4112119 ashish4112119
  • 16-08-2022

Answer:

b = √112

Step-by-step explanation:

a^2 + b^2 = c^2

3^2 + b^2 = 11^2

b^2 = c^2 − a^2

b^2 = 11^2 − 3^2

√b^2 = √11^2 − 3^2

b =√11^2 − 3^2

b = √11^2 − 3^2

b = √121 − 9

b = √112

Answer Link

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