emilybb195
emilybb195
19-03-2017
Mathematics
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Аноним
Аноним
19-03-2017
[tex]\large\begin{array}{I} \mathtt{ \dfrac{4}{x^3} - \dfrac{2x-1}{3x} = \dfrac{4 \times 3-x^2(2x-1)}{3x^3} =\dfrac{12-2x^3+x^2}{3x^3}} \end{array}[/tex]
The answer is C.
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v to the power of 2 =47
