Respuesta :

[tex](16x^3-12x^2+4x):4x=\frac{16x^3-12x+4x}{4x}=\frac{16x^3}{4x}-\frac{12x^2}{4x}+\frac{4x}{4x}\\\\=\underline{\underline{4x^2-3x+1}}\leftarrow Answer[/tex]