alexwing285 alexwing285

16-05-2017
Mathematics

contestada

What is the product?
A. [tex] \frac{k+1}{k^2} [/tex]
B. [tex] \frac{k-1}{k^2} [/tex]
C. [tex] \frac{-1}{k} [/tex]
D. [tex] \frac{1}{k} [/tex]

$What is the product A tex frack1k2 tex B tex frack1k2 tex C tex frac1k tex D tex frac1k tex class=$

Respuesta :

WojtekR WojtekR

16-05-2017

[tex]\dfrac{3k}{k+1}\cdot\dfrac{k^2-1}{3k^3}=\dfrac{3k(k+1)(k-1)}{3k^3(k+1)}=\dfrac{k-1}{k^2}[/tex]

Answer B.

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