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jessiccagirtman
I got a common denominator on the terms with 'a' in them and then added the coefficients.
Ver imagen jessiccagirtman
mjankiewicz
[tex]-\frac{2}{3}a+\frac{5}{6}a-\frac{1}{6}=-\frac{4a}{6}+\frac{5a}{6}-\frac{1}{6}=\frac{-4a+5a-1}{6}=\frac{a-1}{6}[/tex]