angelarobinson0 angelarobinson0
  • 17-06-2017
  • Mathematics
contestada

evaluate the expression 14C2

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jdoe0001 jdoe0001
  • 17-06-2017
[tex]\bf _nC_r= \cfrac{n!}{r!(n-r)!}\qquad \qquad _{14}C_2=\cfrac{14!}{2!(14-2)!}[/tex]
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