tierneytribett tierneytribett
  • 19-07-2017
  • Mathematics
contestada

Find the 6th term of a geometric sequence t3 = 444 and t7 = 7104.

Respuesta :

RickyChen
RickyChen RickyChen
  • 19-07-2017
Given the value of t3 and t7, and t7 = t3 * r^4, where r represents the geometric quotient. 

So 7104 = 444 * r^4 -> solve for r, you will get r = 2 or -2

So, for r = 2, t6 = t7 / r = 7104 / 2 = 3552

For r = -2, t6 = -3552
Answer Link
Аноним Аноним
  • 19-07-2017
if we divide the 7th term by the third it gives us r^4   (  common ratio to power 4).

r^4 = 7104/444 =   16

so r =  4th root of 16  = 2

So 6th term will be the 7th term / 2 = 7104 / 2 =  3552

Answer Link

Otras preguntas

Isaac read 32% of oeople owned dogs what fraction of people owned dogs
Which of the following is NOT indicated by Mendel’s experiments? (A) incomplete dominance (B) segregation (C) recessive (D) dominant (E) independent assortment
how do i Subtract and simplify: (11x2 + 7) – (6x2 + 3x – 3)
Find the 8th term of geometric sequence {a_{n}, n = 1, 2, 3, . . .} with common ratio r = 0.5 and first term a_{1} = 2.
What is FOIL and PEMDAS?
draw 8 lines that are between 1 inch and 3 inches long measures each line to the nearest fourth inch and make a line plot
The school owns 2 classroom sets of 30 calculators each, which students are required to have during their mathematics class. There are 2 calculators from one se
How to solve -5/7-11/7x=-y 2y=7+5x
Choose the two equations you would use to solve the absolute value equation below. Then solve the two equations.|x + 5| = 55
factor each polynomial  5xy-10x