jeremyleejieming jeremyleejieming
  • 21-01-2024
  • Mathematics
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find the smallest whole number h such that 4704 divided by h is a cube number

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ayenoe13
ayenoe13 ayenoe13
  • 21-01-2024

Answer:

Step-by-step explanation:

First, factorize 4704 into its prime factors: 4704=266×3×7^2

Next, group the prime factors into triples, since a cube number has three equal factors: 4704=(2^3)^2×3×(7^2)^1

Then, find the product of the unpaired factors, which are 3 and 7^2: 3×7^2=147

Finally, divide 4704 by 147 to get the smallest whole number h: 4704/​147​=32

The smallest whole number h such that 4704 divided by h is a cube number is 16.

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