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Willchemistry
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Molar mass NaCl = 58.44 g/mol

number of moles:

n = m / mm

n = 15.0 / 58.44

n = 0.2566 moles of NaCl

Volume in Kg :

50.0 g / 1000 => 0.05 Kg

Therefore :

Molality = moles of solute / volume

Molatity = 0.2566 / 0.05

Molality = 5.132 mol/kg
22nlin

Answer:

C. 5.17

Explanation:

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