lulu109
lulu109
18-08-2017
Mathematics
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If x-y doesn't equal 0 then x^2-y^2 / x-y =
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apologiabiology
apologiabiology
18-08-2017
recognize the differnce of 2 perfect squares
a²-b²=(a-b)(a+b)
so
[tex]\frac{x^2-y^2}{x-y}=\frac{(x-y)(x+y)}{x-y}=(\frac{x+y}{1})(\frac{x-y}{x-y})=(x+y)(1)=x+y[/tex]
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