Respuesta :

cmw15drums
x < 0

First, distribute the 8 to (6x+2)
48x + 16

-6 + 16 +48x < 7x + 10

Combine like-terms
48x - 7x < 10 + 6 - 16

Simplify
41x < 0

Therefore, x < 0
[tex]-6+8(6x+2) \ \textless \ 7x+10[/tex] 

[tex]8(6x+2)-6\ \textless \ 7x+10[/tex] 

[tex]48x+16-6\ \textless \ 7x+10[/tex] 

[tex]48x+10\ \textless \ 7x+10[/tex] 

[tex]48x\ \textless \ 7x [/tex] 

[tex]48x-7x\ \textless \ 0[/tex] 

[tex]41x\ \textless \ 0[/tex]

[tex]x\ \textless \ 0[/tex]

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