grgrsmb
grgrsmb
16-11-2017
Mathematics
contestada
4^2-6(2^x)-16=0
solve for x
Respuesta :
altavistard
altavistard
17-11-2017
Assuming that
4^2-6(2^x)-16=0 is correct, we can rearrange it as:
-6(2^x) + 4^2 - 16=0
Are you sure it's not
6(2^x) + 4^2 - 16=0 ?
If 6(2^x) + 4^2 - 16=0 is correct, then
6(2^x) + 4^2 - 16=16 - 16 = 0, that is, 6(2^x) = 0. Then x = 0 (answer)
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