By the segment addition postulate,
AB = AC+CB
since C is somewhere between A and B
We know AC is 0.618 and AB = 1
CB = x for now
AB = AC+CB
1 = 0.618+x
1-0.618 = 0.618+x-0.618 ... subtract 0.618 from both sides
0.382 = x
x = 0.382
So CB is 0.382 units long
To find the ratio of AC to CB, divide the values
AC/CB = 0.618/0.382 = 1.618 (approximate to 3 decimal places)
Answer: Choice B) 1.618
