keeandre7
keeandre7
17-01-2018
Mathematics
contestada
x+2y=4 3z=-3 x+2y-z=1
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altavistard
altavistard
17-01-2018
X+2y=4 3z=-3 x+2y-z=1 becomes
X+2y=4
3z=-3
x+2y-z=1
If 3z= -3, then z = -1.
Then we have
X+2y=4 => x+2y = 4
3z=-3
x+2y-z=1 => x+2y-(-1)=1 => x+2y = 0
The graphs of these two straight lines never cross, so the system has NO SOLUTION.
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