First we rewrite the function:
f (x) = 3 * (2) ^ x
Then, we have the following fact that is a fact of the problem:
"exponential graph passing through point 0, 5"
Thus,
Original graphic:
f (x) = 3 * (2) ^ x
f (0) = 3 * (2) ^ 0
f (0) = 3
Graph with transformation:
g (x) = 3 * (2) ^ x + 2
g (0) = 3 * (2) ^ 0 + 2
g (0) = 3 + 2
g (0) = 5
Go through the point (0, 5)
Therefore the graph is:
g (x) = 3 * (2) ^ x + 2
g (x) = f (x) + 2
answer:
f (x) + 2
