Answer:
m∠ACB = 32°
Step-by-step explanation:
It is given in the question that AC is tangent on a circle at A.
m∠ACB = 58° then we have to tell the measurement of ∠ABC.
In ΔABC, ∠BAC = 90° (since radius of a circle is always ⊥ to the tangent drawn)
Therefore in ΔABC
∠ABC + ∠BAC + ∠ACB = 180°
∠ACB + 90 + 58 = 180
∠ACB = 180 - (90 + 58) = 180 - 148 = 32°
Finally m∠ ACB = 32° is the answer.
